9x^2+60x-56=0

Solution for 9x^2+60x-56=0 equation:

9x^2+60x-56=0

a = 9; b = 60; c = -56;
Δ = b2-4ac
Δ = 602-4·9·(-56)
Δ = 5616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5616}=\sqrt{144*39}=\sqrt{144}*\sqrt{39}=12\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{39}}{2*9}=\frac{-60-12\sqrt{39}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{39}}{2*9}=\frac{-60+12\sqrt{39}}{18}
$